WebbQ: Find the pH of a 0.145 M HCIO2 (aq) solution. For HCIO2, Ka = 0.011. O 0.84 O 1.46 O 1.34 O 1.40 A: Given: Concentration of HClO2 = 0.145 M And Ka of HClO2 = 0.011 Q: A voltaic cell consists of an Mn/Mn2+ half-cell and a Cd/Cd2+ half-cell. Calculate [Mn2+] when… A: Click to see the answer Webb3 apr. 2024 · The expression of the base dissociation constant will be Kb = x ⋅ x 0.49 −x Kb = x2 0.49 −x Now, you didn't provide a value for the base dissociation constant, but I can tell you that it's small enough to allow you to use the approximation 0.49 −x ≈ 0.49 This means that you have Kb = x2 0.49 and so x = √0.49⋅ Kb
Express 0.01 as a percentage - Everyday Calculation
Webb14 apr. 2024 · To dissociate state and outcome uncertainty, our experimental design uses a previously described mathematical model of risk (Preuschoff et al., 2008). Hence, we … WebbThe ability to discriminate between painful stimuli of different intensities is fundamental to pain perception, but its neural underpinnings are poorly understood. With neuroimaging techniques, Zhang et al. demonstrate that this ability is reliably and selectively encoded by pain-evoked brain responses, laying the foundation for objective pain assessment. rayman classic download pc
What is the "pH" of a "0.49-M" "NaClO" solution? Socratic
Webb28 mars 2024 · In the present study, we asked whether processes that lead to vigilance decrement and processes that foster the propensity for mind-wandering (MW) can be … WebbIf Kf for water is 1.86∘C /molal then the apparent percentage of dissociation is: A 60% B 78% C 100% D 50% Solution The correct option is A 78% ∵ ΔT f =iKfm ∴ i = 0.062 0.01×1.86 = 0.062 0.0186= 10 3 K3[F e(CN)6] dissociates as, 3K+ +[F e(CN)6]3− ∴ i = (1−x)+3x+x 1 = 10 3 ⇒ 3 - 3x + 9x + 3x = 10 9x = 7 ⇒ x= 7 9 Webb0.011 as a percent is 1.1% where, 0.011 is a decimal, 1.1% is a percentage. For values other than 0.011, use this below tool: SUBMIT. How-to: 0.011 as a Fraction. The below … simplex clock